What will be printed out if you attempt to compile and run the following code? int i=9; switch (i) { default: System.out.println("default"); case 0: System.out.println("zero"); break; case 1: System.out.println("one"); case 2: System.out.println("two"); }
default
default, zero
error default clause not defined
no output displayed
When the switch expression i=9 doesn't match any case label (0, 1, or 2), execution falls through to the default case. The default case prints 'default' but has no break statement, so execution continues to the next case (case 0) which prints 'zero'. The break after case 0 stops further fallthrough. Therefore the output is 'default' followed by 'zero' on the next line.
To answer this question, let's go through each option to understand why it is correct or incorrect:
Option A) default - This option is incorrect because the code will print more than just "default" as the output.
Option B) default, zero - This option is correct. The code will print "default" and "zero" as the output.
Option C) error default clause not defined - This option is incorrect. The code does have a default clause.
Option D) no output displayed - This option is incorrect. The code will display output.
The correct answer is B. This option is correct because when the switch statement is executed, it will match the value of 'i' to the case statements. Since 'i' has a value of 9, it does not match any of the case statements and falls through to the default case. Therefore, "default" will be printed. Then, the execution will continue to the next case statement, which is case 0. Since there is no break statement after the case 0, the execution will continue to the next case statement, which is case 1. Therefore, "zero" will also be printed.
So, the output of the code will be "default, zero".