Multiple choice

For each of the following pairs of equations find the relationship between (x) & (y). ( )(I) (2x^2 - 10x + 12 = 0) ( )(II) (4y^2 - 16 = 0)

  1. $If \(x > y\)$
  2. $If \(x < y\)$
  3. $If \(x \geq y\)$
  4. $If \(x \leq y\)$
  5. $If \(x = y\) or no relation between \(x\) and \(y\) can be established$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Equation I: 2x² - 10x + 12 = 0 factors to (x-2)(x-3)=0, so x = 2 or 3. Equation II: 4y² - 16 = 0 gives y² = 4, so y = 2 or -2. Comparing: when x=2, x=y=2; when x=3, x>y (3 > 2, 3 > -2). Thus x is always greater than or equal to y, making option C correct.

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