Given below are two quantities named I and II. Based on the given data, you have to determine the relation between them and mark the answer Probability of picking a red ball out of a box is 3/7 , box contains only red, blue and white ball and white balls are 40% more than blue balls. Quantity I: Probability of picking one white balls. Quantity II: when white balls are removed from box then probability of picking one blue ball.

Let total balls = T. Red probability = 3/7, so red balls = (3/7)T. Let blue balls = B. White balls are 40% more than blue, so white = 1.4B. Total balls: Red + Blue + White = T, so (3/7)T + B + 1.4B = T. Solving: (3/7)T + 2.4B = T, so 2.4B = (4/7)T, giving B = T/4.2 = (10/42)T = (5/21)T. White = 1.4B = 1.4 × (5/21)T = (7/21)T = (1/3)T. Quantity I: Probability of white = White / Total = (1/3)T / T = 1/3. Quantity II: After removing white balls, probability of blue = Blue / (Red + Blue) = ((5/21)T) / ((3/7)T + (5/21)T) = (5/21)T / (14/21)T = 5/14. Comparing 1/3 vs 5/14: 1/3 ≈ 0.333, 5/14 ≈ 0.357. So Quantity I < Quantity II, answer B is correct.