Multiple choice

A bag contains $3$ red and $3$ white balls. Two balls are drawn one by one. The probability that they are of different colours is

  1. $\dfrac {3}{10}$
  2. $\dfrac {2}{5}$
  3. $\dfrac {3}{5}$

  4. None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total ways to draw 2 balls from 6 is 6C2 = 15. The ways to get different colors (1 red, 1 white) is 3C1 * 3C1 = 9. The probability is 9/15, which simplifies to 3/5.

AI explanation

The total ways to draw two balls from 6 is 6C2, which equals 15. The number of ways to draw one red ball and one white ball is 3C1 multiplied by 3C1, which is 9. Using the classical probability formula, 9/15 simplifies to 3/5. The result is 3/5.

Keep practicing — related questions