Ram invested his money (50,000) in two part one in S.I. and other in C.I. if interest he get after 2 year are in ratio 7 : 12 respectively then find the money invested by him in C.I. Given that both scheme give same rate of interest. राम ने अपना पैसा (50,000) दो भाग एक में साधारण ब्याज में और दूसरे को C.I में निवेश किया। यदि 2 वर्ष बाद उसे प्राप्त ब्याज क्रमशः 7:12 के अनुपात में है, तो उसके द्वारा C.I में निवेश की गई धनराशि ज्ञात कीजिए। दोनों योजनाएँ समान ब्याज दर देती हैं।

Let amount in SI = x, amount in CI = (50000 - x), rate = r%. After 2 years, SI = (x × r × 2)/100, CI = (50000 - x)[(1 + r/100)² - 1]. Given SI:CI = 7:12. The rate cancels out: 2x/100 : (50000 - x)(2r/100 + r²/10000) = 7 : 12. This gives: 2x : (50000 - x)(200r + r²)/100 = 7 : 12. Without knowing r, we get x : (50000 - x) = 7(200r + r²) : 2400. This cannot be solved uniquely as r is unknown. However, if we use the simplified CI formula approximation: CI ≈ (50000 - x) × 2r/100, then 2xr : 2r(50000 - x) = 7 : 12, giving x : (50000 - x) = 7 : 12, so x = 70000/19 ≈ 18421, CI investment ≈ 31579. But this uses an approximation. The problem states both schemes give same rate but doesn't specify the rate value. Using the exact CI formula requires knowing r. Option E (Cannot be determined) is technically correct because the rate is unspecified and different rate values give different answers. However, if we solve assuming the rate cancels: 7k : 12k where SI = 2xr/100 and CI = (50000 - x)[(1+r/100)²-1]. This gives multiple possible values for x depending on r.