A jar contains a mixture of mango juice and water in the ratio of 22: 3 respectively. 50 liters of mixture was taken out and 25 liters of water was added to the jar. If water was 34% in the resultant mixture, what was the initial quantity of mix¬ture in the jar? (In liter)

Let the initial mixture be x liters. Water = 3/25 x, Mango juice = 22/25 x. After removing 50L, water removed = 6L and mango removed = 44L. After adding 25L water, total water = (3x/25 - 6 + 25) = (3x/25 + 19). Total mixture = (x - 50 + 25) = (x - 25). Given: water is 34% of resultant mixture, so (3x/25 + 19)/(x - 25) = 34/100. Solving: 3x + 475 = 0.34(25x - 625) = 8.5x - 212.5, which gives 5.5x = 687.5, so x = 125. Option B is correct.