The side of the triangle are 10cm, 24cm, and 26cm, At each of vertices, circle of the radius 3.5 cm are drawn. What is the area of the triangle excluding the portion covered by the sector of the circle?

Triangle with sides 10, 24, 26 is right-angled (10²+24²=26²). Area = ½ × 10 × 24 = 120 cm². Sectors at vertices have radii 3.5 cm and angles equal to the vertex angles (sum = 180° for right triangle). Total sector area = (180/360) × π × 3.5² = ½ × 38.48 = 19.24 cm². Area excluding sectors = 120 − 19.24 = 100.76 ≈ 100.75 cm². Wait, that assumes sum of angles is 180°, but in a right triangle, the three angles sum to 180°, with one angle = 90°. So total sector area = (90/360 + A/360 + B/360) × πr² = (180/360) × πr² = 19.24. Then 120 − 19.24 = 100.76, which rounds to 100.75. Option B is correct.