Multiple choice technology

What will happen if you try to compile and run the following code? public class Q { public static void main(String argv[]){ int anar[]=new int[5]; System.out.println(anar[0]); } }

  1. Error: anar is referenced before it is initialized

  2. null

  3. 0

  4. 5

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

In Java, array elements are automatically initialized to default values when the array is created. For int arrays, all elements are initialized to 0. The code prints anar[0] which is 0, not null (that's for object arrays).

AI explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) Error: anar is referenced before it is initialized - This option is incorrect. In the given code, the array anar is initialized using the statement int anar[]=new int[5];. This creates an array of size 5 with default values of 0 for each element. Therefore, there is no error in referencing anar[0] in the System.out.println statement.

Option B) null - This option is incorrect. The array anar is not assigned a value of null. It is initialized with default values of 0 for each element.

Option C) 0 - This option is correct. Since the array anar is initialized with default values of 0 for each element, anar[0] will have a value of 0. Therefore, the output of the System.out.println statement will be 0.

Option D) 5 - This option is incorrect. The value 5 is not assigned to any element of the anar array, so it is not the correct output.

The correct answer is C) 0. This option is correct because the code initializes the array with default values of 0, so anar[0] will have a value of 0.