Multiple choice

In each of the following question, two equations are I and II given. You have to solve them and give answer. I. (5x^2 - 8x = -3) II. (4y^2 - 16y = -15)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Rewrite equation I: 5x² - 8x + 3 = 0 factors to (5x - 3)(x - 1) = 0, giving x = 0.6 or x = 1. Rewrite equation II: 4y² - 16y + 15 = 0 factors to (2y - 3)(2y - 5) = 0, giving y = 1.5 or y = 2.5. Both x values (0.6, 1) are less than both y values (1.5, 2.5), so x < y is correct.

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