Multiple choice

If a cylinder of radius 3.5 meter and height 27 meter is melted and constructed into three identical cone of 3 meter height. What will be the radius of each cone ? एक बेलन जिसकी त्रिज्या 3.5 मी. और ऊँचाई 27 मी. है को पिघलाकर तीन बराबर शंकु बनाए जाते हैं। जिनकी ऊँचाई 3 मी. है तो प्रत्येक शंकु की त्रिज्या क्या होगी ?

  1. 10.25 m/मी.

  2. 10.5 m/मी.

  3. 9 m/मी.

  4. 12.5 m/मी.
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B Correct answer
Explanation

Volume of cylinder = πr²h = π × 3.5² × 27 = π × 12.25 × 27 = 330.75π. This volume is divided equally among 3 cones, so each cone has volume 110.25π. Volume of cone = (1/3)πR²H. For height 3m: (1/3)πR² × 3 = πR² = 110.25π. So R² = 110.25, giving R = 10.5m.

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