Multiple choice

The curved surface area of a cylindrical pole is 528 m2 and its volume is 1848 m3. Find the ratio of radius to height? यदि एक बेलनाकार खम्भे के वक्रपृष्ठ का क्षेत्रफल 528 मी.2 है तथा इसका आयतन 1848 मी.3 है तो उस बेलनाकार खम्भे की त्रिज्या तथा ऊँचाई का अनुपात ज्ञात कीजिए।

  1. 7 : 9

  2. 7 : 12

  3. 14 : 9

  4. 12 : 7
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B Correct answer
Explanation

CSA = 2πrh = 528, so h = 12/r. Volume = πr²h = 1848. Substituting h gives πr²(12/r) = 1848, so πr(12) = 1848, giving r = 7. Then h = 12/7, so r:h = 7:12. The ratio of radius to height is 7:12.

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