Multiple choice

In each question two equations numbered I and II are given, you have to solve both the equation and choose the correct answer. $I. (4x^2 - 14x + 12 = 0)$ $II. (2y^2 - 3y + 2 = 0)$

  1. X > Y

  2. X < Y

  3. X ≤ Y

  4. X ≥ Y

  5. X = Y or the relationship can’t be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving equation I: 4x² - 14x + 12 = 0 factors to 2(2x² - 7x + 6) = 0, giving (2x-3)(x-2) = 0. So x = 2 or x = 1.5. Solving equation II: 2y² - 3y + 2 = 0 has discriminant = 9 - 16 = -7 < 0, so no real roots. Since x has real values (2 and 1.5) while y has no real solutions, we cannot establish a relationship between x and y. Hence 'relationship can't be established'.

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