Multiple choice

The curved surface area of a cylindrical rod is 264 m2. and its volume is 924 m3. The ratio of its semi diameter to height is - एक बेलनाकार छड़ का पार्श्व पृष्ठ क्षेत्रफल 264 मी.2 है और इसका आयतन 924 मी.3 है | इसके अर्द्ध व्यास का इसकी ऊँचाई से अनुपात है -

  1. 3 : 7

  2. 7 : 3

  3. 6 : 7

  4. 7 : 6

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D Correct answer
Explanation

CSA = 2πrh = 264, Volume = πr²h = 924. Dividing: (πr²h)/(2πrh) = 924/264 = r/2 = 7/2. So r = 7. Semi-diameter (radius) : height = 7 : 6. This ratio can be derived from the formulas.