(\text{In each of the following questions, two equations are given. You have to solve them and Give answer})(\text{(I)}) (5x^2 + 69x = -234\\text{(II)}) (13y^2 + 660 = -217y)

Solve both quadratic equations and compare x and y values. Equation I: 5x² + 69x + 234 = 0. Using quadratic formula or factorization, discriminant = 69² - 4(5)(234) = 4761 - 4680 = 81, so x = [-69 ± 9]/10, giving x = -6 or x = -7.8. Equation II: 13y² + 217y + 660 = 0. Discriminant = 217² - 4(13)(660) = 47089 - 34320 = 12769, giving two real roots. Since x can be -6 while y might be different, or vice versa, the relationship cannot be uniquely established without computing both exact y values.