Multiple choice

2 years ago a man was 6 times as old as his son. After 18 years he will be twice as old his son. Find the sum of their present ages ?

  1. 37 years

  2. 39 years

  3. 40 years

  4. 41 years

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let son's present age be x and father's present age be y. Two years ago: (y-2) = 6(x-2), so y = 6x-10. After 18 years: (y+18) = 2(x+18). Substituting y: (6x-10+18) = 2x+36, giving 4x = 28, so x=7. Then y = 6(7)-10 = 32. Sum of present ages = 7+32 = 39 years. The answer is option B.

Keep practicing — related questions