Multiple choice

In the following questions two equations (I) and (II) are given. You have to solve both the equation and give answer- ( (I) ) ( 4y^2 + 24y + 35 = 0 ) ( (II) ) ( 4x^2 – 25x + 39 = 0 )

  1. If x ≥ y

  2. If x ≤ y

  3. If x > y

  4. If x < y

  5. If x = y or the relationship can not be established.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving equation (I) for y: 4y² + 24y + 35 = 0. Using quadratic formula: y = (-24 ± √(576 - 560))/8 = (-24 ± √16)/8 = (-24 ± 4)/8. So y = -20/8 = -5/2 or y = -28/8 = -7/2. Solving equation (II) for x: 4x² - 25x + 39 = 0. Factorizing: (4x-13)(x-3) = 0, so x = 13/4 or x = 3. Comparing: x values are 3.25 and 3, while y values are -2.5 and -3.5. Both x values are greater than both y values, so x > y.

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