In each of the following questions, two equations are given. You have to solve them and answer the question.( (I) x^2 – 21x + 104 = 0 )( (II) y^2 – 28y +195 = 0 )

Factorizing equation (I): x² - 21x + 104 = (x - 13)(x - 8) = 0, so x = 13 or x = 8. Factorizing equation (II): y² - 28y + 195 = (y - 15)(y - 13) = 0, so y = 15 or y = 13. Comparing values: when x = 8, both y values (13, 15) are greater (x < y). When x = 13, y can be 13 (x = y) or 15 (x < y). Since x is never greater than y and x = y is possible, x ≤ y is correct.