Multiple choice

In each of the following questions, two equations are given. You have to solve them and answer the question. (I) (2x^2 + 13x + 21 = 0) (II) (3y^2 + 34y + 63 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For 2x²+13x+21=0: factorizing gives (2x+7)(x+3)=0, so x = -7/2 or -3. For 3y²+34y+63=0: factorizing gives (3y+7)(y+9)=0, so y = -7/3 or -9. Comparing: x=-3.5 or -3; y≈-2.33 or -9. We have x=-3.5 < y=-2.33, x=-3.5 > y=-9, x=-3 < y=-2.33, x=-3 > y=-9. Since x is sometimes less than y and sometimes greater, the relationship cannot be established.

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