Solve the following equation: $x^2-7x+12=0$
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Solve the following equation: $x^2-7x+12=0$
The quadratic equation x^2 - 7x + 12 = 0 can be factored as (x-3)(x-4) = 0. Thus, the roots are x = 3 and x = 4.
We factor the quadratic equation x^2 - 7x + 12 = 0 by finding two numbers that multiply to 12 and add to -7. These numbers are -3 and -4, allowing us to write the equation as (x - 3)(x - 4) = 0. Setting each factor to zero gives the roots x_1 = 3 and x_2 = 4.