What is the result of trying to compile and run this program. public class Test{ public static void main(String[] args){ int[] a = {1}; Test t = new Test(); t.increment(a); System.out.println(a[a.length - 1]); } void increment(int[] i){ i[i.length - 1]++; } }

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  1. Compiler error.

  2. Compiles and runs printing out 2

  3. Compiles and runs printing out 1

  4. An ArrayIndexOutOfBounds Exception at runtime

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Correct Option: B

AI Explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) Compiler error - This option is incorrect. There are no syntax errors in the given code, so it will compile successfully.

Option B) Compiles and runs printing out 2 - This option is correct. The code initializes an array a with a single element 1. It then creates an instance of the Test class and calls the increment method, passing in the array a. The increment method increments the value of the last element in the array. After the method call, the value of a[a.length - 1] will be 2, and this value is printed out using System.out.println.

Option C) Compiles and runs printing out 1 - This option is incorrect. The value of a[a.length - 1] is modified to 2 inside the increment method, so it will be printed as 2, not 1.

Option D) An ArrayIndexOutOfBounds Exception at runtime - This option is incorrect. The code does not access any elements outside the bounds of the array, so it will not throw an ArrayIndexOutOfBoundsException.

The correct answer is B. It compiles and runs, printing out 2 because the increment method modifies the last element of the array.

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