Multiple choice

In the following questions, two equations numbered I and II are given. You have to solve both the equations and given answer.\newline I. (3a^2 - 2a - 1 = 0)\newline II. (6b^2 + 11b + 3 = 0)

  1. If a < b

  2. If a ≤ b

  3. If a > b

  4. If a ≥ b

  5. If a = b or the relationship cannot be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solve equation I: 3a² - 2a - 1 = 0 factors as (3a+1)(a-1) = 0, so a = 1 or a = -1/3. Solve equation II: 6b² + 11b + 3 = 0 factors as (3b+1)(2b+3) = 0, so b = -1/3 or b = -3/2. Comparing values: a = 1 > both b values; a = -1/3 equals b = -1/3 and exceeds b = -3/2. Thus a ≥ b always.

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