Multiple choice

Solve the following quadratic equation by factorization : $(a \, + \, b)^2x^2 \, - \, 4abx \, - \, (a \, - \, b)^2 \, = \, 0$ The roots are 1, $-\left(\dfrac{a \, - \, b}{a \, + \, b} \right )^2$

  1. True

  2. False
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A Correct answer
Explanation

Factoring (a+b)^2 x^2 - 4abx - (a-b)^2 = 0. The roots are x = 1 and x = -((a-b)/(a+b))^2 is incorrect. The roots are actually 1 and -((a-b)/(a+b))^2 is not the standard factorization result for this specific quadratic.

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