Multiple choice

In each of the following questions, two equations (I) and (II) are given. You have to solve them and answer the question.(\text{(I)}) (4x^2 + 19x + 21 = 0)(\text{(II)}) (2y^2 - 23y + 63 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving equation (I): 4x²+19x+21=0 factors to (4x+7)(x+3)=0, giving x=-7/4=-1.75 or x=-3. Solving equation (II): 2y²-23y+63=0 factors to (2y-7)(y-9)=0, giving y=3.5 or y=9. Since x=-1.75 or -3 (both negative) and y=3.5 or 9 (both positive), x

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