Multiple choice

In each of the following questions, two equations are given. You have to solve them and give answer-(\text{(I)}) (x^2 + 3x + 2 = 0)(\text{(II)}) (2y^2 = 5y)

  1. If x>y

  2. If x≥y

  3. If x<y

  4. If x≤y

  5. If x=y or relationship can not be established

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving (I): x² + 3x + 2 = 0 gives x = -2 or x = -1. Solving (II): 2y² - 5y = 0 gives y(2y - 5) = 0, so y = 0 or y = 5/2. Comparing: -2 < 0, -2 < 2.5, -1 < 0, -1 < 2.5. All possible x values are less than all possible y values, so x < y.