Multiple choice

In each of the following questions two equations are given. You have to solve them and give answer - (I) (a^{2} + 5a + 6 = 0) (II) (b^{2} + 7b + 12 = 0)

  1. $If \(a < b\)$
  2. $If \(a > b\)$
  3. $If \(a \le b\)$
  4. $If \(a \ge b\)$
  5. $If \(a = b\) or Relationship cannot be determine$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

For equation I: a² + 5a + 6 = 0 factors as (a+2)(a+3) = 0, giving a = -2 or a = -3. For equation II: b² + 7b + 12 = 0 factors as (b+3)(b+4) = 0, giving b = -3 or b = -4. Comparing values: a can be -2 or -3; b can be -3 or -4. When a = -2, a > b (since -2 > -3 and -2 > -4). When a = -3, a ≥ b (since -3 = -3 and -3 > -4). Therefore, in all cases a ≥ b is true, making option D correct.

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