The arrangement of the following quadratic equations in the descending order of their sum of the roots. A: $ x^{2}+11=0$ B: $(x+2) (x-3) =0$ C: $5x^{ 2 }+4x=0$ D: $2x^{ 2 }+3x-5=0$

Use the relationship between roots and coefficients where the sum of the roots of a quadratic equation equals negative b divided by a. The sums of the roots for the four equations are 0 for A, 1 for B, negative 4 divided by 5 for C, and negative 3 divided by 2 for D. Arranging these values in descending order gives 1, 0, negative 4 divided by 5, and negative 3 divided by 2. The result is B, A, C, D.

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