Multiple choice

In each of the following questions, two equations are given. You have to solve them and $( (I) 5x^2 – 13x – 6 = 0 )( (II) 3y^2 + 8y + 4 = 0 )$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
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A Correct answer
Explanation

Solve (I): 5x² - 13x - 6 = 0 factors to (5x + 2)(x - 3) = 0, giving x = 3 or x = -0.4. Solve (II): 3y² + 8y + 4 = 0 factors to (3y + 2)(y + 2) = 0, giving y = -2 or y = -2/3. Comparing: x = 3 > both y values; x = -0.4 > -2 and > -0.67. So x > y always.

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