Multiple choice

In the following questions two equations numbered (I) and (II) are given. You have to solve both equations and give answer— $(I) (8x^2 + 6x = 5) (II) (12y^2 - 22y + 8 = 0)$

  1. if x < y

  2. if x > y

  3. if x ≤ y

  4. if x ≥ y

  5. if x = y or relation cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving equation (I): 8x² + 6x - 5 = 0 gives x = 1/2 or x = -5/4. Solving equation (II): 12y² - 22y + 8 = 0 gives y = 7/6 or y = 2/3. When x = 0.5, we have x < 1.167 but x > 0.667, so the relationship between x and y varies. No single inequality consistently holds.

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