Multiple choice

In each of the following questions, two equations (I) and (II) are given. You have to solve them and $( (I) \ 3x + 2y = 14 \\ (II) \ x + 4y = 13 )$ Give answer

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can not be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving the system: Multiply equation (II) by 3 to get 3x + 12y = 39. Subtract (I) from this: (3x+12y) - (3x+2y) = 39-14, giving 10y = 25, so y = 2.5. Substituting in (II): x + 4(2.5) = 13, so x + 10 = 13, giving x = 3. Since x = 3 and y = 2.5, we have x > y. Option B (x ≥ y) is incorrect because x is strictly greater than y, not equal to it. Option C (x < y) and D (x ≤ y) are both false since x > y.

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