Train A crossed a stationary train 39 seconds it also crossed a man standing on a platform in 19 seconds the length of the train. A is 456 meter. What is the length of the statuary ?

When Train A crosses a man in 19 seconds, its length passes a point: speed = 456/19 m/s. When it crosses a stationary train in 39 seconds, it covers its own length plus the stationary train's length. Let stationary train length = L. Then (456+L)/(456/19) = 39. Solving: 456+L = 39×(456/19) = 39×24 = 936, so L = 936-456 = 480 meters. Option D is correct.