Multiple choice

The largest number that divides 248 and 1029, leaving remainder 40 and 5 respectively is – वह सबसे बड़ी संख्या जिससे कि 248 और 1029 से विभाजित करने पर क्रमशः 40 व 5 शेषफल प्राप्त हो-

  1. 16

  2. 18

  3. 17

  4. 15
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A Correct answer
Explanation

To find the largest number that divides 248 and 1029 leaving remainders 40 and 5, we first subtract the remainders: 248-40=208 and 1029-5=1024. Then we find HCF(208,1024). Factorizing gives 208=2^4×13 and 1024=2^10, so HCF=16. This is the largest number satisfying both conditions since any number >40 that divides 208 cannot divide 1024.

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