Multiple choice

If y be the least number, which when divided by 5, 6, 7 and 8 leaves a remainder 3 in each case but when divided by 9 leaves no remainder. The sum of digits of y is

  1. 21

  2. 22

  3. 24

  4. 18
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Number is of form LCM(5,6,7,8) × k + 3 = 840k + 3, and must be divisible by 9. Testing values: k=1 gives 843 (sum=15, not ÷9), k=2 gives 1683 (sum=18, ÷9). So y = 1683. Sum of digits = 1 + 6 + 8 + 3 = 18. Option A (21) would require y with digit sum 21, but 2523 ÷ 9 = 280.33. Option C (24) would need digit sum 24, but checking values divisible by 9 doesn't yield such sum.

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