Multiple choice

What is the smallest positive number, which when divided by 3, 4 and 5 will have a remainder of 2?

  1. 22

  2. 42

  3. 62

  4. 122
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

LCM of 3, 4, 5 is 60. We need a number that leaves remainder 2 when divided by each, so number = 60k + 2. For k=1: 62 (smallest positive). Check: 62÷3=20 remainder 2, 62÷4=15 remainder 2, 62÷5=12 remainder 2. Option A (22) = 60×0+22 gives wrong remainders. Option B (42) fails for divisor 4. Option D (122) is 60×2+2 but not smallest.

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