Multiple choice

A person goes from point A to point B with a speed of 55 km/hr and returns back with a speed of 65 km/hr. What is the average speed (in km/hr) of the person while going and coming back from point A to point B?

  1. 59.58

  2. 62.31

  3. 60

  4. 63
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A Correct answer
Explanation

Average speed for a round trip is (2 * v1 * v2) / (v1 + v2). (2 * 55 * 65) / (55 + 65) = 7150 / 120 = 59.5833.

AI explanation

Because the distances going and returning are equal, use the harmonic mean formula for average speed: 2xy / (x + y). Substituting the two speeds gives (2 * 55 * 65) / (55 + 65), which equals 7150 / 120. This simplifies to an average speed of 59.58 km/hr.

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