Multiple choice

Directions: In the following question, two equations numbered I and II are given. You have to solve both the equations and give answer accordingly. I. 20x2 - 31x + 12 = 0 II. 4y2 + 5y - 6 = 0

  1. x > y

  2. x ≥ y

  3. x < y

  4. x ≤ y

  5. x = y or no relationship can be established between x and y
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

I: 20x^2 - 31x + 12 = 0 -> (4x-3)(5x-4) = 0 -> x = 0.75, 0.8. II: 4y^2 + 5y - 6 = 0 -> (4y-3)(y+2) = 0 -> y = 0.75, -2. Comparing: x >= y is true since 0.75=0.75 and 0.8 > -2.

AI explanation

For equation one, factor the quadratic 20x squared minus 31x plus 12 to get (5x minus 4)(4x minus 3) equals 0, which gives x equals 0.8 or x equals 0.75. For equation two, factor the quadratic 4y squared plus 5y minus 6 to get (4y minus 3)(y plus 2) equals 0, which gives y equals 0.75 or y equals negative 2. Since both values of x are greater than or equal to the values of y, the relationship is x is greater than or equal to y.

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