Given the following code: public class Demo { public int method(int x) { int r = 1; r += x; if ((x > 4) && (x < 10)) { r += 2 * x; } else (x <= 4) { r += 3 * x; } else { r += 4 * x; } r += 5 * x; return r; } public static void main(String [] args) { Demo ob = new Demo(); System.out.println("OF(11) is: " + ob.method (11)); } } What is the result?

technology programming languages

  1. OF(11) is: 45

  2. OF(11) is: 56

  3. Compilation fails.

  4. Runtime Exception

Show answer
Correct Option: C

AI Explanation

To determine the result of the given code, let's analyze the code step by step.

The code defines a class named "Demo" with a method named "method". The method takes an integer parameter "x" and returns an integer.

Inside the "method" method, there is a variable "r" initialized to 1. The variable "r" is then incremented by the value of "x" using the "+=" operator.

Next, there is an if-else statement. The condition is (x &gt; 4) &amp;&amp; (x &lt; 10). If the condition is true, the code inside the if block is executed, otherwise, the code inside the else block is executed.

Inside the if block, the variable "r" is incremented by 2 times the value of "x" using the "+=" operator.

Inside the else block, there is another else statement. This is a syntax error because an else statement should not have a condition. Therefore, the code will fail to compile.

Since the code fails to compile, the correct answer is C) Compilation fails.

Find more quizzes: