A contractor undertakes to complete a job in 60 days and employs 90 persons for the same. After 45 days, when he takes a review, he finds that 90% of the work is over. In order to finish the work in 60 days, how many persons should he now remove from this job?

Using the standard work formula of M1 times D1 divided by W1 equals M2 times D2 divided by W2, we substitute the given values. For the first period, 90 persons times 45 days divided by 9 parts of work equals the new number of persons times 15 days divided by 1 part of work. Solving this equation gives the required number of persons as 30. Since the contractor currently has 90 persons, he must remove 60 persons to finish on time.

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