An alloy contains copper and tin in the ratio 3 : 2, respectively. If 250 gm of copper is added to this alloy, then the copper in it becomes double the quantity of tin in it. What is the amount (in gm) of tin in the alloy?

Let the initial amounts of copper and tin be 3x and 2x, respectively, based on the 3 to 2 ratio. Adding 250 gm of copper makes the new copper quantity 3x plus 250, which the problem states is double the amount of tin (2x). Setting up the equation 3x plus 250 equals 4x yields x equals 250. Therefore, the amount of tin is 2 multiplied by 250, resulting in 500 gm.

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