Multiple choice

Find the smallest number which when divided separately by 15, 20, 36 and 48, leaves 3 as a remainder in each case.

  1. 183

  2. 243

  3. 483

  4. 723
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Find LCM of 15, 20, 36, 48. 15 = 3*5, 20 = 2^2*5, 36 = 2^2*3^2, 48 = 2^4*3. LCM = 2^4 * 3^2 * 5 = 16 * 9 * 5 = 720. Number = LCM + remainder = 720 + 3 = 723.

AI explanation

We first find the least common multiple of 15, 20, 36, and 48, which is 720. Since each division leaves a remainder of 3, we add 3 to this LCM. The sum of 720 and 3 is 723.

Keep practicing — related questions