Multiple choice

Two years ago, a man was four times as old as his son. In another two years, he will be thrice as old as his son. What are their present ages, respectively?

  1. 34 years; 10 years

  2. 24 years; 8 years

  3. 36 years; 11 years

  4. 24 years; 18 years
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A Correct answer
AI explanation

Let the present ages of the man and his son be M and S. Two years ago, M - 2 = 4(S - 2), simplifying to M = 4S - 6. In another two years, M + 2 = 3(S + 2), giving M = 3S + 4. Equating the two expressions for M gives 4S - 6 = 3S + 4, so S = 10. Substituting S back gives M = 4(10) - 6 = 34, so their present ages are 34 years and 10 years.

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