Multiple choice

How many natural numbers are there between 1000 to 2000, which when divided by 341 leave remainder 5?

  1. 3

  2. 2

  3. 4

  4. 1
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A Correct answer
Explanation

Number = 341 * k + 5. Range: 1000 < 341k + 5 < 2000. 995 < 341k < 1995. k = 3 (1023), k = 4 (1364), k = 5 (1705). There are 3 such numbers.

AI explanation

The required numbers take the form 341k plus 5. For k equals 3, the number is 341 times 3 plus 5, which equals 1028. For k equals 4, the number is 341 times 4 plus 5, which equals 1369. For k equals 5, the number is 341 times 5 plus 5, which equals 1710. All three values fall between 1000 and 2000, so there are 3 such natural numbers.

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