To answer this question, let's go through the code and analyze its execution:
The given code defines a method called divide that takes two parameters a and b. Inside the method, there is a try-catch-finally block.
The code inside the try block attempts to divide a by b and assigns the result to c. However, since the code doesn't do anything with c, this operation is unnecessary.
If an exception occurs during the division (e.g., if b is 0), the catch block will catch the exception and execute the code inside it. In this case, it prints "Exception ".
After the try-catch block, the code inside the finally block will always execute, regardless of whether an exception occurred or not. In this case, it prints "Finally".
Now, let's analyze the options:
Option A) Prints out: Exception Finally - This option is incorrect because it suggests that both "Exception" and "Finally" will be printed. However, only "Finally" will be printed because no exception will occur.
Option B) Prints out: Finally - This option is correct. In the given code, since no exception occurs, only "Finally" will be printed.
Option C) Prints out: Exception - This option is incorrect because "Exception" will only be printed if an exception occurs during the division. In this case, no exception occurs.
Option D) Compile with error - This option is incorrect because the code will compile without any errors.
The correct answer is B) Prints out: Finally. This option is correct because the finally block will always execute, regardless of whether an exception occurred or not.