Multiple choice technology programming languages

. What is the output for the below code ? public class Test{ public static void main(String argv[]){ Test1 pm1 = new Test1("One"); pm1.run(); Test1 pm2 = new Test1("Two"); pm2.run(); } } class Test1 extends Thread{ private String sTname=""; Test1(String s){ sTname = s; } public void run(){ for(int i =0; i < 2 ; i++){ try{ sleep(1000); }catch(InterruptedException e){} yield(); System.out.println(sTname); } } }

  1. Compile error

  2. One One Two Two

  3. One Two One Two

  4. One Two
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The code calls run() directly, not start(), so no actual threading occurs. Each Test1 runs its run() method sequentially in the main thread. Each loop prints twice, so 'One One Two Two' is the output.

AI explanation

To determine the output of the given code, let's go through the code step by step:

  1. In the Test class's main method:

    • Create an instance of the Test1 class named pm1 and pass the string "One" as an argument to its constructor.
    • Call the run method of pm1.
    • Create another instance of the Test1 class named pm2 and pass the string "Two" as an argument to its constructor.
    • Call the run method of pm2.

  2. In the Test1 class:

    • Declare a private instance variable sTname of type String and initialize it with an empty string.
    • Define a constructor that takes a string argument and assigns it to the sTname variable.
    • Override the run method of the Thread class.
    • In the run method:
      • Iterate from 0 to 1 (two iterations).
      • Within each iteration:
      • Use the sleep method to pause the execution for 1000 milliseconds (1 second).
      • Use the yield method to give up the CPU to other threads.
      • Print the value of sTname.

Based on the above code, the output will be:

One One Two Two

Therefore, the correct answer is B) One One Two Two.

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