What is the output for the below code ? public class Test { public static void main(String... args) { Pattern p = Pattern.compile("a{3}b?c*"); Matcher m = p.matcher("aaab"); boolean b = m.matches(); System.out.println(b); } }

  1. true

  2. Compile Error

  3. false

  4. NullPointerException


Correct Option: A
Explanation:

To solve this question, the user needs to know the basics of regular expressions and the use of the Pattern and Matcher classes in Java. The given code compiles a regular expression pattern and matches it with the string "aaab". The regular expression pattern "a{3}b?c*" means that the pattern should start with three "a" characters, optionally followed by a single "b" character, and then zero or more "c" characters.

The Matcher.matches() method tries to match the entire input sequence against the pattern. If the entire input sequence matches the pattern, the method returns true; otherwise, it returns false.

In this case, the input sequence "aaab" matches the pattern "a{3}b?c*", because it starts with three "a" characters and ends with zero "c" characters. The optional "b" character is present in the input sequence, but it is not required to match the pattern.

Therefore, the output of the code will be:

The Answer is: A (true)

Find more quizzes: