Multiple choice technology mainframe

Determine the total number of bytes in the following. 01 REC-1. 02 FIRST-GROUP. 03 A1 PIC X(4). 03 A2 PIC 99. 02 REDEFINES FIRST-GROUP. 03 A3 PIC 999. 03 A4 PIC 999. 02 THIRD-GROUP. 03 A5 OCCURS 5 TIMES PIC 99.

  1. 22

  2. 16

  3. 12

  4. 14
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Calculating bytes: FIRST-GROUP = A1(4) + A2(2) = 6 bytes. SECOND-GROUP REDEFINES FIRST-GROUP so it shares the same 6 bytes = A3(3) + A4(3). THIRD-GROUP = A5 occurs 5 times with PIC 99 (2 bytes each) = 10 bytes. Total = 6 + 10 = 16 bytes.

AI explanation

To determine the total number of bytes in the given structure, we need to consider the size of each field and group.

Let's go through each line to calculate the total number of bytes:

01 REC-1 - This is a level 01 group and does not contribute to the byte count.

02 FIRST-GROUP - This is a level 02 group and does not contribute to the byte count.

03 A1 PIC X(4) - This field has a length of 4 bytes.

03 A2 PIC 99 - This field has a length of 2 bytes.

02 REDEFINES FIRST-GROUP - This is a level 02 group and does not contribute to the byte count.

03 A3 PIC 999 - This field has a length of 3 bytes.

03 A4 PIC 999 - This field has a length of 3 bytes.

02 THIRD-GROUP - This is a level 02 group and does not contribute to the byte count.

03 A5 OCCURS 5 TIMES PIC 99 - This field occurs 5 times and each occurrence has a length of 2 bytes. So, the total length for this field is 5 * 2 = 10 bytes.

Adding up the byte counts for each field, we have:

4 + 2 + 3 + 3 + 10 = 22 bytes.

Therefore, the correct answer is A) 22.

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