Given: 11. public static void test(String str) { 12. int check = 4; 13. if (check = str.length()) { 14. System.out.print(str.charAt(check -= 1) +“, “); 15. } else { 16. System.out.print(str.charAt(0) + “, “); 17. } 18. } and the invocation: 21. test(”four”); 22. test(”tee”); 23. test(”to”); What is the result?

technology programming languages

  1. r, t, t,

  2. r, e, o,

  3. Compilation fails.

  4. An exception is thrown at runtime.

Show answer
Correct Option: C

AI Explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) r, t, t - This option is incorrect because the code will not compile.

Option B) r, e, o - This option is incorrect because the code will not compile.

Option C) Compilation fails. - This option is correct. The code will not compile because there is an error in line 13. The error occurs because a single equal sign (=) is used instead of a double equal sign (==) in the if statement.

Option D) An exception is thrown at runtime. - This option is incorrect because the code will not compile.

The correct answer is C. Compilation fails. This option is correct because there is an error in the code that prevents it from compiling.

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