Multiple choice technology programming languages

Given: 11. String test= “a1b2c3”; 12. String[] tokens = test.split(”\d”); 13. for(String s: tokens) System.out.print(s +“ “); What is the result?

  1. a b c

  2. 1 2 3

  3. a1b2c3

  4. Compilation fails
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The regex \d matches each digit character. String.split() removes these digit delimiters, producing an array [a, b, c]. The enhanced for loop prints each token followed by a space, resulting in a b c. Trailing empty strings are discarded by default in Java's split method.

AI explanation

To determine the result of the given code, let's go through each line:

  1. String test = "a1b2c3"; - This line declares and initializes a String variable named "test" with the value "a1b2c3".

  2. String[] tokens = test.split("\d"); - This line splits the string "test" using the regular expression "\d", which matches any digit. The result is an array of strings, where each element contains the substrings separated by digits. In this case, the array will contain ["a", "b", "c"].

  3. for(String s : tokens) System.out.print(s + " "); - This line iterates over each element in the "tokens" array and prints it followed by a space. The output will be "a b c".

Therefore, the result of the given code is:

A) a b c

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