Multiple choice technology programming languages

Given: 11. public class Test { 12. public static void main(String [] args) { 13. int x =5; 14. boolean b1 = true; 15. boolean b2 = false; 16. 17.if((x==4) && !b2) 18. System.out.print(”l “); 19. System.out.print(”2 “); 20. if ((b2 = true) && b1) 21. System.out.print(”3 “); 22. } 23. } What is the result?

  1. 2

  2. 3

  3. 1 2

  4. 2 3

  5. 1 2 3

  6. Compilation fails.
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The first if condition ((x==4) && !b2) evaluates to false because x==4 is false (x is 5), so the short-circuit && doesn't evaluate !b2 and "1" is not printed. Line 19 prints "2" unconditionally. The second if ((b2 = true) && b1) first assigns true to b2, then evaluates (true && b1) which is true since b1 is true, so "3" is printed. Final output: "2 3". Option E is incorrect because the first condition is false. Option F is incorrect - the code compiles and runs successfully.

AI explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) 2 - This option is incorrect because the code does not print only "2".

Option B) 3 - This option is incorrect because the code does not print only "3".

Option C) 1 2 - This option is incorrect because the code does not print "1" at any point.

Option D) 2 3 - This option is correct because the code prints "2" and "3" in the output.

Option E) 1 2 3 - This option is incorrect because the code does not print "1" at any point.

Option F) Compilation fails - This option is incorrect because there are no syntax errors in the code provided.

The correct answer is Option D, which is "2 3". This option is correct because the code prints "2" and "3" in the output.

Let's understand the code:

  • Line 13 initializes the variable x with the value 5.
  • Line 14 initializes the boolean variable b1 with true and b2 with false.
  • Line 17 checks if the condition (x==4) && !b2 is true. Since x is not equal to 4 and !b2 is true (negation of false), the condition is false.
  • Line 20 assigns the value true to b2 and then checks the condition (b2 = true) && b1. Since b2 is now true and b1 is also true, the condition is true.
  • Line 21 prints "3" in the output.

Therefore, the output of the code will be "2 3".

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