Given: 10. public class Bar { 11.static void foo(int...x) { 12. // insert code here 13. } 14. } Which two code fragments, inserted independently at line 12, will allow the class to compile? (Choose two.)

  1. foreach(x) System.out.println(z);

  2. for(int z : x) System.out.println(z);

  3. while( x.hasNext()) System.out.println( x.next());

  4. for( int i=0; i< x.length; i++ ) System.out.println(x[i]);


Correct Option: B,D

AI Explanation

To determine the two code fragments that will allow the class to compile, let's go through each option:

Option A) foreach(x) System.out.println(z); - This option is incorrect because the "foreach" loop syntax is incorrect. It should be for (int z : x) to iterate through the elements of the x array.

Option B) for(int z : x) System.out.println(z); - This option is correct because it uses the enhanced "for" loop (also known as the "foreach" loop) to iterate through the elements of the x array. This syntax is valid and will allow the class to compile.

Option C) while( x.hasNext()) System.out.println( x.next()); - This option is incorrect because it assumes that x is an iterator object with the methods hasNext() and next(). However, in the given code, x is declared as a variable of type int[] (an array), which does not have these methods. Therefore, this option is incorrect.

Option D) for( int i=0; i&lt; x.length; i++ ) System.out.println(x[i]); - This option is correct because it correctly uses a basic "for" loop to iterate through the elements of the x array. It initializes a counter variable i to 0, checks if i is less than the length of the array x, and increments i in each iteration. The syntax x[i] is used to access the elements of the array. This option is valid and will allow the class to compile.

Therefore, the correct options are B) for(int z : x) System.out.println(z); and D) for( int i=0; i&lt; x.length; i++ ) System.out.println(x[i]);.

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