Given: 10. public class Bar { 11.static void foo(int...x) { 12. // insert code here 13. } 14. } Which two code fragments, inserted independently at line 12, will allow the class to compile? (Choose two.)
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foreach(x) System.out.println(z);
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for(int z : x) System.out.println(z);
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while( x.hasNext()) System.out.println( x.next());
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for( int i=0; i< x.length; i++ ) System.out.println(x[i]);
Varargs parameters in Java are treated as arrays. Iterating over x can be done using either an enhanced for-loop for(int z : x) or a standard index-based loop. foreach is not a Java keyword, and arrays do not have iterator methods like hasNext() or next().
To determine the two code fragments that will allow the class to compile, let's go through each option:
Option A) foreach(x) System.out.println(z); - This option is incorrect because the "foreach" loop syntax is incorrect. It should be for (int z : x) to iterate through the elements of the x array.
Option B) for(int z : x) System.out.println(z); - This option is correct because it uses the enhanced "for" loop (also known as the "foreach" loop) to iterate through the elements of the x array. This syntax is valid and will allow the class to compile.
Option C) while( x.hasNext()) System.out.println( x.next()); - This option is incorrect because it assumes that x is an iterator object with the methods hasNext() and next(). However, in the given code, x is declared as a variable of type int[] (an array), which does not have these methods. Therefore, this option is incorrect.
Option D) for( int i=0; i< x.length; i++ ) System.out.println(x[i]); - This option is correct because it correctly uses a basic "for" loop to iterate through the elements of the x array. It initializes a counter variable i to 0, checks if i is less than the length of the array x, and increments i in each iteration. The syntax x[i] is used to access the elements of the array. This option is valid and will allow the class to compile.
Therefore, the correct options are B) for(int z : x) System.out.println(z); and D) for( int i=0; i< x.length; i++ ) System.out.println(x[i]);.