To determine the value of y at the end of main, let's go through the code step by step:

const int x = 5;
int main(int argc, char** argv)
{
    int x[x];
    int y = sizeof(x) / sizeof(int);
    return 0;
}

In this code, we have a constant integer x initialized with the value of 5.

Next, we declare an array x with the size of x, which is 5. This means we are declaring an array with 5 elements.

Then, we calculate the value of y by dividing the size of the array x (which is 5 * sizeof(int)) by the size of an int (sizeof(int)).

The sizeof operator returns the size of a data type in bytes. In this case, sizeof(int) returns the size of an int in bytes.

Since the size of an int is typically 4 bytes, the size of the array x is 20 bytes (5 * 4).

Therefore, y is equal to the size of the array x (20 bytes) divided by the size of an int (4 bytes), which is 5.

Hence, the correct answer is B) 5.

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